7b^2-9b+2=0

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Solution for 7b^2-9b+2=0 equation: 



7b^2-9b+2=0

a = 7; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·7·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-5}{2*7}=\frac{4}{14}
=2/7
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+5}{2*7}=\frac{14}{14}
=1
$

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